Android ListView实现任意layout

jopen 9年前

SimpleAdapter adapter = new SimpleAdapter(this, getData(),                  R.layout.timenotes_item_left, new String[] { "text1", "text2",                          "text3" }, new int[] { R.id.textView2, R.id.textView3,                          R.id.textView4 }) {              @Override              public View getView(int position, View convertView, ViewGroup parent) {                  Map itemData = (Map) getItem(position);                  int type = Integer.parseInt(itemData.get("type").toString());                  View itemView = null;                  switch (type) {                  case 0:                      Log.d("adapter", "type 0");                      itemView = View.inflate(getApplicationContext(),                              R.layout.timenotes_item_left, null);                      break;                  case 1:                      Log.d("adapter", "type 1");                      itemView = View.inflate(getApplicationContext(),                              R.layout.timenotes_item_right, null);                      break;                  default:                      Log.d("adapter", "type default");                      break;                  }                  return itemView;              }          };          ListView listView = (ListView) findViewById(R.id.listView1);          listView.setAdapter(adapter);